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Las Vegas Freestyle Chess Grand Slam

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Las Vegas Freestyle Chess Grand Slam
Tournament information
SportChess variant (Chess960)
LocationLas Vegas, United States
Dates16 July 2025–20 July 2025
Tournament
format(s)
Single-elimination tournament with round-robin seeding round
Host(s)Freestyle Chess Operations
VenuePavillon Chesnaie du Roy
Participants16
Final (Cape Town) →

The Las Vegas Freestyle Chess Grand Slam is a Chess960 tournament that takes place in Las Vegas, United States from 16 July to 20 July 2025. It is the fourth leg of the Freestyle Chess Grand Slam Tour, a series of Chess960 tournaments being held throughout 2025.[1]

Regulation changes

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While the second leg had 12 participants playing in the main event, the number of participants was increased to 16 for the fourth leg. Howeverer, while before only the top eight players after the round-robin stage qualified for the main knockout bracket, now all the remaining eight players will still play for positions 3-16 in a double-elimination style format.[2]

Qualification

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Main event

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Participants

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Leading up to the later-to-be-called third leg of the Grand Slam Tour, the Grenke Freestyle Chess Open, the organizers of the Freestyle Tour and the Grenke Open announced to publish a world rating list for Freestyle based on the tournament results.[3]

In the newest edition of their Rules and Regulation, Freestyle Chess increased the number of players in a Grand Slam to 16 and replaced the qualification by FIDE rating with the Freestyle rating.

Qualification method Player Age Classical Rating World
Ranking
Freestyle
Rating[4]
(June 2025)
The top three finishers in the previous closed Grand Slam Norway Magnus Carlsen (winner) 34 2837 1 2909
United States Hikaru Nakamura (runner-up) 37 2804 2 2818
United States Fabiano Caruana (third place) 32 2777 4 2804
World Chess Champion India Gukesh Dommaraju (withdrew) 19 2776 5 2701
Winner of the Grenke Freestyle Chess Open Iran Parham Maghsoodloo (runner-up, replacement for Carlsen) 24 2691 38 2712
Winner of the Aeroflot Open 2025 FIDE Ian Nepomniachtchi 34 2757 10 2771
The three highest rated players in Freestyle Ranking India R Praggnanandhaa 19 2767 7 2773
Germany Vincent Keymer 20 2730 22 2766
France Alireza Firouzja (withdrew) 22 2766 8 2764
Wild cards[a] India Arjun Erigaisi 21 2782 3 2760
Uzbekistan Nodirbek Abdusattorov 20 2767 6 2720.8
United States Leinier Dominguez Perez 41 2738 18 2749
United States Levon Aronian 42 2742 16 2758
United States Wesley So 31 2745 14 2737
India Vidit Gujrathi 30 2720 25 2713
Uzbekistan Javokhir Sindarov 19 2710 29 2702
Kazakhstan Bibisara Assaubayeva 21 2509 547 2506
Winner of the online play-in United States Hans Niemann 22 2736 20 2722
Sources:[5]

Group Stage

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White Group

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Black Group

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Knockout Stage

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Upper Bracket

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Quarterfinals Semifinals Grand Final
         
 
 
 
 
 
 
 
 
 
 
 
 
 
 

Lower Bracket

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Lower Quarterfinals Intermediate Red Intermediate Green Lower Semifinals 3rd Place Final
1
2
5
11 6
12 3
4
7
15 8
16 1
2
3
4
13
28 14
28 7
8
15
31 16
32

5th and 7th place Finals

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References

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  1. ^ From Freestyle Chess Players Club (FCPC) members.
  1. ^ "Freestyle Chess' Grand Slam Tour Will Make its U.S. Debut at Wynn Las Vegas". www.freestyle-chess.com. Retrieved 2025-06-03.
  2. ^ "Official Rules and Regulations" (PDF). Retrieved 2025-06-03.
  3. ^ "3.000 Teilnehmer und Freestyle-Rating". 2025-04-08. Retrieved 2025-06-03.
  4. ^ "Freestyle rating" (PDF). Retrieved 2025-06-23.
  5. ^ "Freestyle Chess lands in Las Vegas". Freestyle Chess. Retrieved 2025-06-23.