Jump to content

Brocard's conjecture

From Wikipedia, the free encyclopedia
Unsolved problem in mathematics
Are there at least 4 prime numbers between two consecutive squared prime numbers?

Introduction

[edit]

In number theory, Brocard's conjecture is the conjecture that there are at least four prime numbers between (pn)2 and (pn+1)2, where pn is the nth prime number, for every n ≥ 2.[1] The conjecture is named after Henri Brocard. It is widely believed that this conjecture is true[2]. However, it remains unproven as of 2025. Legendre's conjecture that there is a prime between consecutive integer squares directly implies that there are at least two primes between prime squares for pn ≥ 3 since pn+1pn ≥ 2[3].

Mathematical Statement

[edit]

Let be the -th prime, and let be the number of prime numbers . Formally, Brocard's conjecture claims:

This is equivalent to saying that there are at least primes between squared consecutive primes other than and .

Relation to other Open Problems in Mathematics

[edit]

Legendre's Conjecture

[edit]

Legendre's conjecture claims that there is a prime number between and for all natural number . It is an unsolved problem in mathematics as of 2025. If Legendre's conjecture is true, it immediately implies a weak version of Brocard's conjecture[4]:

Cramér's Conjecture

[edit]

Cramér's conjecture claims that , which gives a bound on how far apart primes can be. Cramér's conjecture implies Brocard's conjecture for sufficient [3].

Oppermann's Conjecture

[edit]

Oppermann's conjecture claims that there is a prime in the interval and in the interval . This unsolved problem directly implies Brocard's conjecture.

Proof that Oppermann's Conjecture implies Brocard's Conjecture

We begin with the fact that , meaning that the minimal interval between primes is . Then, according to Oppermann's conjecture, there is a prime in the interval , a prime in the interval , a prime in the interval , and a prime in the interval . Then, we have:

Which implies at least primes between and , and because , there are at least primes between any two squared consecutive primes, which is exactly what Brocard's conjecture claims.

Examples

[edit]
n Prime numbers
1 2 4 5, 7 2
2 3 9 11, 13, 17, 19, 23 5
3 5 25 29, 31, 37, 41, 43, 47 6
4 7 49 53, 59, 61, 67, 71, ... 15
5 11 121 127, 131, 137, 139, 149, ... 9
stands for .
A gif of the equation of Brocard's conjecture, illustrating the threshold.
The equation graphed up to . The dotted line is the threshold that Brocard's conjecture claims to hold for all .

It is easy to verify the conjecture for small :

The number of primes between prime squares is 2, 5, 6, 15, 9, 22, 11, 27, ... OEISA050216. See the table (right) for a list of primes sorted by the difference. See the animation (right) for the first differences.

Current Research and Results

[edit]

Unconditional Results

[edit]

Bertrand's Postulate

[edit]

A trivial result from Bertrand's postulate, a proven theorem, states that because there is a prime in the interval , and the length of the interval is much greater than , Bertrand's postulate suggests many primes in the interval , though not a sharp bound.

Baker-Harman-Pintz Bound

[edit]

Using the bound proven by Baker et al.[5], that , one can show that there exist infinitely many such that there is at least one prime in the interval , which is a much weaker result than Brocard's conjecture.

Conditional Results

[edit]

Legendre's Conjecture - Weak Version of Brocard's Conjecture

[edit]

As shown above, Legendre's conjecture implies a weak version of Brocard's conjecture but is a strictly weaker conjecture.

Oppermann's Conjecture - Full Proof of Brocard's Conjecture

[edit]

As shown above, Oppermann's conjecture directly implies Brocard's conjecture for large enough , which constitutes a proof of Brocard's conjecture.

Cramér's Conjecture - Full Proof of Brocard's Conjecture

[edit]

As shown above, Cramér's conjecture implies Brocard's conjecture directly.

The Riemann Hypothesis - Full Proof of Brocard's Conjecture

[edit]

The Riemann Hypothesis implies the bound , which implies Brocard's conjecture for sufficiently large , similarly to Cramér's conjecture[6].

See also

[edit]

Notes

[edit]
  1. ^ Weisstein, Eric W. "Brocard's Conjecture". MathWorld.
  2. ^ Guy, Richard K. (2004). Unsolved problems in number theory. Problem books in mathematics (3rd ed.). New York: Springer. ISBN 978-0-387-20860-2.
  3. ^ a b Ribenboim, Paulo (2004). The little book of bigger primes (2nd ed.). New York: Springer. ISBN 978-0-387-20169-6.
  4. ^ Hardy, Godfrey H.; Wright, Edward M.; Silverman, Joseph H. (2008). Heath-Brown, D. R. (ed.). An introduction to the theory of numbers. Oxford mathematics (Sixth ed.). Oxford New York Auckland: Oxford University Press. ISBN 978-0-19-921986-5.
  5. ^ Baker, R. C.; Harman, G.; Pintz, J. (2001). "The Difference Between Consecutive Primes, II". Proceedings of the London Mathematical Society. 83 (3): 532–562. doi:10.1112/plms/83.3.532. ISSN 1460-244X.
  6. ^ Montgomery, Hugh L.; Vaughan, Robert C. (2006). Multiplicative Number Theory I: Classical Theory. Cambridge Studies in Advanced Mathematics. Cambridge: Cambridge University Press. doi:10.1017/cbo9780511618314. ISBN 978-0-521-84903-6.